The number of words, with or without meaning that can be formed by taking 4 letters at a time

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Solution

Find the number of words that satisfy the given arrangement conditions (adsbygoogle = window.adsbygoogle || []).push({}); The word SYLLABUS has the following letters,SS,Y,LL,A,B,U. (Five different letters, two repeated twice)We need 4 letter words with 2 similar and 2 dissimilar letters.The two similar letters can be chosen in C12 ways.The two dissimilar letters can be chosen in C2 5 ways.Now the four letters can be arranged in 4!2! ways.Hence, the total number of words satisfying the given arrangement =C12×C25×4!2! (adsbygoogle = window.adsbygoogle || []).push({}); =21×5 ×4×3×22×3×2×4×3×22=240Hence, 240 four letter words are formed such that two of the letters are alike and two are different.

How many 4

So, the total arrangement is given by, 10×9×8×7=5040 .

How many words can be formed by taking 4 letters at a time?

Now total number of ways: 1680+18+756=2454.

How many words can be formed by taking 4 letters at a time from the letters of the word personification?

=626. Was this answer helpful?

How many 4

Solution : The word, 'LOGARITHMS' contains 10 different letters.
Number of 4-letter words formed out of 10 given letters
`=""^(10)P_(4)=(10xx9xx8xx7)=5040. `
Hence, the required number of 4-letter words `= 5040.