How many possible four letter code words can be formed using 4 consonants of the English alphabet

Solution : First ten letters of the alphabet can be used i.e A,B, C,D,E, F,G,H, I,J. Four letter code is to be formed.
The first place (from left) can be filled by using any of the 10 alphabets. So, there are 10 ways to fill first place.
Since, repetition is not allowed . So, second place can be filled by remaining 9 alphabets.
So, there are 9 ways to fill second place.
Similarly, third place can be filled by remaining 8 alphabets.
And fourth place can be filled by remaining 7 alphabets.
Hence, the required number of ways in which four letter code can be formed is
=10×9×8×7
=5040

Mark M. answered • 09/30/18

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If a letter can be used more than once, then the number of possibilities is (4)(4)(4)(4) = 44 = 256

 

If each letter is used only once, then the number of possibilities is (4)(3)(2)(1) = 24

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How many possible four letter code words can be formed using 4 consonants of the English alphabet

Arthur D. answered • 09/30/18

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if there is repetition...

there are 4 letters, all different

4*4*4*4=256

if there is no repetition...

4*3*2*1=24

this is a permutation, not a combination

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How many 4 letter codes can be formed using 4 letters?

The answer is 360.

How many 4 letter combinations can be formed from the consonants?

So, the answer will be (4 * 6 * 120) = 2880.

How many 4 letter words can be formed from the alphabet?

If repetition is allowed there are 26 possibilities for each letter. Therefore, there are 26^4 = 456,976‬ possible 4 letter strings if repetition is allowed.

How many four

(b) Since the letters may not be repeated, each of the four letters of the code can be selected in 4 ways. So the required number of four-letter codes = 4×4×4×4=256 4 × 4 × 4 × 4 = 256 .